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Assembly Language: CS401 Assignment No 1 Solution Spring 2019

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Solution of CS401 Assignment No 1 2019 Assembly Language Due Date 16-05-2019



Solution of Assignment is Given Below;

Watch the Video to know that how i solve this assignment with step by step guide



Question-1  Calculate the Effective Address and Physical Address for the following set of values. (10)

Segment: 0xFFFF
Offset =0x0800
Base: 0x0111
Index=0x0001

Solution:

Reference See the Page 37-39from pdf or watch PowerPoint SLide 16 in Chapter 8 (You can check it yourself)

1 - Effective Addressing = Base+off set + index

0x0111
+0x0800
+0x0001

____________________________

Effective Address= 0x0912 <====== Answer

2- Physical Address = Segemnet + Effective Address

0xFFFF+0x0912 = 0x10911 <====== Answer

Question-2  Calculate the Segment Address for the given set of Physical and Effective addresses. (10)

a. Physical address = 0x119B, Effective address = 0x10AB
b. Physical address = 0xFF9B, Effective address = 0x10FF



Solution

Reference See the Page 37-39 from pdf or watch PowerPoint SLide 16 in Chapter 8

a. ) Segment Address = Physical Address – Effective Address = 0x119B – 0x10AB = 0x0F0 <====== Answer

b ) Segment Address = Physical Address – Effective Address = 0xFF9B– 0x10FF = 0x10911 <====== Answer

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2 Comments

  1. Please check the 2nd part of question 2. I calculate it but the answer is different from this.

    ReplyDelete
  2. please MTH603 KI Correct solution share kr dyn
    please..........

    ReplyDelete